Consider the equation 2y – 4x = 12. which equation, when graphed with the given equation, will form a system with one solution? –y – 2x = 6 –y + 2x = 12 y = 2x + 6 y = 2x + 12

  –y – 2x = 6 . . . choice 1

Step-by-step explanation:

Consider the system obtained using the other answer choices:

  -y +2x = 12 . . . choice 2

The result of multiplying the given equation by -1/2 is ...

  -y +2x = -6 . . . . a line parallel to that of answer choice 2. The system would have no solution

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  y = 2x +6 . . . choice 3

Solve the given equation for y by adding 4x and dividing by 2. That will give ...

  y = 2x +6 . . . . a line identical to that of answer choice 3. The system would have an infinite number of solutions.

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  y = 2x +12 . . . choice 4

As we found in the previous discussion, the given line can be written as ...

  y = 2x + 6 . . . . a line parallel to that of answer choice 4. The system would have no solution.

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The attached graph shows the given line and that of answer choice 1.

First one: -y - 2x = 6

Step-by-step explanation:

Coplanar parallel lines never intersect

Given line:

2y - 4x = 12

2y = 4x + 12

y = 2x + 6

Has a slope of 2

Search for the line which doesn't have a slope of 2

-y - 2x = 6

y = -2x - 6

Has a slope of -2, so this line will intersect the given line at one point. Hence one solution

it depends on the weather. because i have flown to seattle when it was pouring down rain and there was one time i flew to ohio when it was snowing hard. whats your situation.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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