The vertices of quadrilateral mnpq are m(-3,-2), n(-1,4), p(2,4), q(4,-2). translate quadrilateral mnpq using the rule (x, y)-> (x+3, y+4)

Therefore, if the vertices of quadrilateral MNPQ given as M(-3,-2), N(-1,4), P(2,4), Q(4,-2) are translated using the rule (x,y)->(x+3, y+4), then the vertices of the quadrilateral M'N'P'Q' are M'(0,  2), N'(2,  8), P'(5,  8), and Q'(7,  2)

The vertices of the quadrilateral are:

M(-3,-2), N(-1,4), P(2,4), Q(4,-2)

The rule of translation is:

(x,y)->(x+3, y+4)

Following the rule of translation above, add 3 to the x-coordinate and 4 to the y-coordinate

The vertices of the quadrilateral M'N'P'Q' are:

M'(-3+3,  -2+4)  =  M'(0,  2)

N'(-1+3,  4 + 4)   =  N'(2,  8)

P'(2+3,  4 + 4)   =  P'(5,  8)

Q'(4+3,  -2+4)   =  Q'(7,  2)

Therefore, if the vertices of quadrilateral MNPQ given as M(-3,-2), N(-1,4), P(2,4), Q(4,-2) are translated using the rule (x,y)->(x+3, y+4), then the vertices of the quadrilateral M'N'P'Q' are M'(0,  2), N'(2,  8), P'(5,  8), and Q'(7,  2)

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Here's what I get.

Step-by-step explanation:

The rule is (x, y) ⟶ (x + 3, y + 4).

That means you must move each point three units to the right and four units up.  Thus,

M(-3, -2) ⟶ M'(0, 2)

N(-1, 4)  ⟶ N'(2, 8)

P(2, 4)    ⟶ P'(5, 8)

Q(4, -2)  ⟶ Q'(7, 2)  

Your quadrilateral is a trapezoid. Both MNPQ and its image M'N'P'Q' are shown in the Figure below.

x-3y=4

step-by-step e

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet