Explain how you would use the
technique of completing the square to
solve the following:
x2 + 6x – 16 = 0

two solutions

x1=-8 , x2=2

Step-by-step explanation:

x^{2}+6x-16=0 move constant to the right

x^{2}=6x=16 add () to both sides of question

x^{2}+6x+()=16+()

x^{2}=6x+()=16+()

using a^{2}+2ab+b^{2}=(a+b)^{2}, factor the expression

[tex](x+\frac{6}{2} ^{2}=25

reduce the fraction with 2

(x+3)^{2}=25

solve for x

the get final solution of x= -8 and x= 2

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

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step-by-step explanation:

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