If i have to move the constant over to one side, what value would i have to add to the left side in order to complete the square?

x² + 4x - 5 = 2

To make the equation complete square , we have to add 11 .

Step-by-step explanation:

Given as :

The linear equation is

x² + 4 x - 5 = 2

Now, move the constant to left side of equation

So, x² + 4 x - 5 - 2 = 0

Or, x² + 4 x - 7 = 0

Now, to make equation complete square , let add 11 both side

So, x² + 4 x - 7 + 11 = 11

Or, x² + 4 x + 4 = 11

Now, applying mid-term break

So,  x² + 2 x + 2 x + 4 = 11

Or, x ( x + 2) + 2 (x + 2) = 11

Or, (x + 2) ( x + 2) = 11

Or, (x + 2)² = 11

Hence, To make the equation complete square , we have to add 11 . Answer

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!