The sum of three numbers is 86 the second number is 9 less than the first the third number is 3 times the first what are the numbers

10, 19 and 57

Step-by-step explanation:

let the first number be a, the second be b and the third be c

a+b+c=86

the second number is 9 less than the first

a=b+9i

b=a-9

the third number is 3 times the first

c=3aii

a=c/3

therefore

b+9=c/3

c=3(b+9)

b+9+b+3(b+9)=86

b+9+b+3b+27=86

collecting like terms

5b=86-(27+9)

5b=86-36

5b=50

therefore

b=10

recall i to solve for a

a=b+9

a=10+9

a=19

recall ii to solve for c

c=3a

c=3*19

c=57

goog may have it for you

answer: 48

just remember to use pemdas:

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