Dennis want to fill 55-gallon drums with a 20% winter mixture of antifreeze for customers. dennis wants to mix 100% antifreeze with a 10% antifreeze mix to get the 20% mixture. how many gallons of 100% antifreeze and 10% antifreeze does he need in order to fill the drum?

The number of gallons of 100% mixture to be added is 6.11 gallons and the 10% mixture to be added is 48.89 gallons.

Step-by-step explanation:

Let us assume that x gallons of 10% mixture and y gallons of 100% mixture are added to make 55 gallons of 20% mixture.

So, x + y = 55 ............. (1)

And

⇒ 0.1x + y = 0.2x + 0.2y

⇒ 0.1x = 0.8y

⇒ x = 8y ........... (2)

So, from equation (1) we get, 8y + y = 55

⇒ 9y = 55

⇒ y = 6.11 gallons.

Therefore, the number of gallons of 100% mixture to be added is 6.11 gallons and a 10% mixture to be added is (55 - 6.11) = 48.89 gallons. (Answer)

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: