Acharity organization is holding a food drive with a goal to collect at least 1,000 cans of food by the end of the month. it currently has 566 cans from donations and is having an event where 87 guests will attend and bring cans. which solution set represents the number of cans each must bring to meet the goal

The correct answer is that each guest attending the event has to bring at least 5 cans of food to meet the goal

Step-by-step explanation:

1. Let's review the information provided to us to answer the problem correctly:

Amount of food cans to collect by the end of the month = 1,000

Food cans collected as of today = 566

Number of guests attending the event = 87

2. Which solution set represents the number of cans each must bring to meet the goal?

For answering this question, we will use the following inequality:

x = Number of food cans that each guest has to bring to meet the goal

566 + 87x ≥ 1,000

Solving for x, we have:

87x ≥ 1,000 - 566

87x ≥ 434

x ≥ 434/87

x ≥ 4.99 ⇒ x ≥ 5

The correct answer is that each guest attending the event has to bring at least 5 cans of food to meet the goal

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2