Aride at a carnival has two types of cars for children to ride one type has two seats and one has four seats there are 25 cars and they can seat a total of 70 children how many four seated cars are there

10

Step-by-step explanation:

To solve this problem you need to create a system of equations. In these equations, use a = 2-seated car and b = 4- seated car

The first equation that you can make can be a + b = 25 because the number of 2-seated cars plus the number of 4-seated cars is going to equal a total of 25 cars.

The next equation you can make is 2a + 4b = 70 because the number of seats provided by the 2-seated cars plus the number of seats provided by the 4-seated cars will equal 70 total seats.

Next, line up the equations and solve:

Step one: Line up the equations

                a +  b = 25

             2a + 4b = 70

Step two: Multiply the top equation by -2 so that you can add both of                                        the equations together

             -2(a) + -2(b) = 25(-2)   ⇒   -2a - 2b = -50

                2a +    4b = 70         ⇒    2a + 4b = 70

Step three: Add the equations

               -2a - 2b = -50

              + 2a + 4b = 70

                         2b = 20

Step four: Divide both sides by 2 in order to solve for b

                2b = 20 ⇒ b = 10  

Because b represents the number of 4-seated cars, you now know that there are 10 4-seated cars on the ride.          

answer is x<

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.