Triangle pqr has coordinates p(–8, 3), q(–8, 6), and r(–3, 6). if the triangle is translated by using the rule (x, y) right-arrow (x + 4, y minus 6), what are the coordinates of triangle p prime q prime r prime?

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

h/o/e/s mad

step-by-step explanation:

si si si

lol 2

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