Did i do this right?
find the equation of the axis of symmetry for the parabola
y=x^2-8x+5

used y=ax^2+bx+c and got a=1 b=-8 and c=5

then used the formula x=-b/2a and plugged that in and got x=- -8/2(1) and simplified to get x=4 as the axis of symmetry.

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph