carlos is changing his health care insurance and deciding between two different pans that charge the same premium.
plan a has a $1,200 deductible with 30% coinsurance. plan b has a $1,500 deductible with 25% coinsurance. carlos had a total of $6,350 in medical bills last year. under which plan would carlos share have been less?
support your answer with mathematical calculations. answer in complete sentence.

Carlos would pay lower out-of-pocket costs if he picks over plan B.

Step-by-step explanation:

Let's make the comparison between plan A and plan B, this way:

Medicals bills = US$ 6,350

Plan A

6,350 - 1,200 = 5,150 * 30% = 5,150 * 0.3 = 1,545

Total out-of-pocket costs = 1,200 + 1,545 = $ 2,745

Plan B

6,350 - 1,500 = 4,850 * 25% = 4,850 * 0.25 = 1,212.50

Total out-of-pocket costs = 1,500 + 1,212.50 = $ 2,712.50

Carlos would pay lower out-of-pocket costs if he picks over plan B.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: