What are the domain and range of the function fix)=-3(x-5)2 +4?

domain of the function are x, 1, 2, 3 and range are 6x-26, -20, -14, -8

Step-by-step explanation:

f(x)=3(x-5)2+4

=(3x-15)2+4

=6x-30+4

=6x-26

if the value of x is 1

f(1)=6×1-26

=-20

if value of x is 2

f(2)=6×2-26

=-14

if the value of x is 3

f(3)=6×3-26

=-8

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: