What is the equation of this circle in standard form?

a) . (x+2)2+(y+3)2=36

b) . (x+2)2+(y+3)2=6

c) . (x−2)2+(y−3)2=6

d) . (x−2)2+(y−3)2=36

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (2, 3 ) and r = 6, thus

(x - 2)² + (y - 3)² = 6², that is

(x - 2)² + (y - 3)² = 36 → D

pls ask

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: