Atriangular prism is 19.1 meters long and has a triangular face with a base of 18 meters and a height of 12 meters. the other two sides of the triangle are each 15 meters. what is the surface area of the triangular prism?

A= 1132.8 m^2

Step-by-step explanation:

l=19.1m

b=18m

h=12m

s=15m

The formula to find surface area of the triangular prism is:

A = bh + 2ls + lb

A = (18×12) + 2(19.1×15) + (19.1×18)

A = 216 + 573 + 343.8

A= 1132.8 m^2

surface Area of triangular prism = 502.5m^2

Step-by-step explanation:

Formular for surface area of a prism is given as: SA=bh+(S1 +S2+S3)H

Given base =18m, length=19.1, h=12, w=15

S1=1/2bh =1/2×18×12 =108m

S2=108m . This is because the dimensions of the two ends of the triangular prism.

S3=lw=19.1×15=286.5m

Surface area=108+108+286.5=502.5m^2

40 is the final : )

i dont know sorry

step-by-step explanation: