What is the horizontal asymptote of f (x) =startfraction negative 2 x over x + 1 endfraction? y = –2 y = –1 y = 0 y = 1

  y = -2

Step-by-step explanation:

Any asymptotes of a rational function will be described by the quotient of the numerator and denominator (excluding any remainder).

The horizontal asymptote is ...

  y = -2

Step-by-step explanation:

The given function is

An asymptote refers to a restriction in the domain or range set of the function. This happens to rational functions, because there's a scenario where the function is undetermined: when its denominator is zero.

So, in this case, the value that makes the denominator zero is

That means, we need to restrict the domain for . But this is a vertical asymptote.

To find horizontal asymptotes, we need to find the restrictions for the range of the function, we do that isolating .

So, if we analyse the denominator

Therefore, the restriction is . In other words, the vertical asymptote is the first choice.

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step-by-step explanation:

answer: it is 8

step-by-step explanation:

you know why its 8