The length of a rectangle is 3m less than double the width, and the area of the rectangle is 44m to the second power. Find the dimensions of the rectangle

length = 8m and width = 5.5m

Step-by-step explanation:

Let the width be w

Length = 2w - 3

Given, Area = 44m2

Remember, area = length x width

Area = (2w - 3) X w.    (expand the bracket)

Area = 2w² - 3w

2w² - 3w = 44

2w² - 3w - 44 = 0

Solve the quadratic equation

2 Factors of -44 that the sum would give -3 = +8 & -11

Rewrite the equation

2w² +8w - 11w -44 = 0 (factorise)

2w(w +4) - 11 ( w + 4) = 0

(2w - 11) ( w + 4) = 0

2w - 11 =0 or w + 4 = 0

2w = 11 or w = -4

W = 11/2 or -4

Width = 5.5m because we can't have a width that is negative.

Therefore length = 2w - 3

Length = 2(5.5) - 3

Length = 11 -3

Length = 8m

Dimension of rectangle is length = 8m and width = 5.5m

That is 8m by 5.5m

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to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s