The length of a rectangle is 5cm more than it's width. If the width is increased by 2 cm and the length is increased by 3 cm a new rectangle is formed that has an area of 46 cm squared more than the original rectangle. Find dimensions of the original rectangle.

The dimensions of the original rectangle are:

Length 11 cm

Width 6 cm

Step-by-step explanation:

Let

x ----> the original length

y ----> the original width

we know that

The original area is

----> equation A

----> equation B

The new area is

----> equation C

----> equation D

substitute equation A and equation C in equation D

----> equation E

substitute equation B in equation E

solve for y

(

Find the value of x

therefore

The dimensions of the original rectangle are:

Length 11 cm

Width 6 cm

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

hiking down a winding trail.

step-by-step explanation: