A GPC experiment (refractive index detector) yields the following results for an experimental poly(isobutylene) (PIB) sample:elutiondetector elution detectortime, minresponse time, min response29.5 0 35.0 4.6 30.0 0 35.5 2.7 30.5 0.7 36.0 2.3 31.0 2.1 36.5 1.5 31.5 3.3 37.0 1.1 32.0 4.9 37.5 0.7 32.5 3.8 38.0 0.4 33.0 2.7 38.5 0.2 33.5 2.8 39.0 0.1 34.0 3.7 39.5 0 34.5 5.5 40.0 0 Draw the structure of PIB with all atoms. Three nearly monodisperse PIBsamples (M = 2x105, 2x104, and 2x103 g/mol) are injected into the instrument producing sharp peaks at retention times of 31.5, 35.6, and 39.5 min. What are Mn, Mw, and the PDI for this sample? Note: Keep proper track of the calibration data.

answer: ask

step-by-step explanation:

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.