Scores on a college entrance exam are normally distributed with a mean of 550 and a standard deviation of 100. Find the value that represents the 90th percentile of scores. Answer with a whole number.

The value that represents the 90th percentile of scores is 678.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the value that represents the 90th percentile of scores.

This is the value of X when Z has a pvalue of 0.9. So X when Z = 1.28.

The value that represents the 90th percentile of scores is 678.

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two