Problem is on the attached picture. Thanks!

Cost of ribeye steak dinner is $19.058

Cost of grilled salmon dinner is $14.88

Solution:

Let x be the ribeye steak dinner and y be the grilled salmon dinner.

Write the given equation in the algebraic form.

First day sold:

15x + 21 y = 598.34 – – – – (1)

Second day sold:

25x + 7y = 580.61 – – – – (2)

To solve these equations by elimination method.

Multiply equation (2) by 3, we get

75x + 21y = 1741.83 – – – – (3)

Now, subtract equation (1) from equation (3).

75x + 21y – (15x + 21y)= 1741.83 – 598.34

75x + 21y – 15x – 21y = 1143.49

60x = 1143.49

Divide by 60 on both sides of the equation.

x = 19.058

Substitute x value in equation (2), we get

25(19.058) + 7y = 580.61

476.45 + 7y = 580.61

Subtract 476.45 on  both sides of the equation.

7y = 104.16

Divide by 7 on both sides of the equation.

y = 14.88

Cost of ribeye steak dinner is $19.058

Cost of grilled salmon dinner is $14.88.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a