The length that a hanging spring stretches varies directly with the weight placed at the end of the spring. If a weight of 15lb 15⁢lb stretches a certain spring 19in. 19⁢in. , how far will the spring stretch if the weight is increased to 30lb 30⁢lb ? (Leave the variation constant in fraction form. Round off your final answer to the nearest in.)

the spring would be stretched by 38 inches.

Step-by-step explanation:

The length that a hanging spring stretches varies directly with the weight placed at the end of the spring. Let L represent the length of the spring and let w represent the weight placed at the end of the spring. Introducing a constant of variation, k, the expression would be

L = kW

If a weight of 15lb stretches a certain spring 19in, the expression would be

19 = 15k

k = 19/15

The equation would be

L = 19w/15

if the weight is increased to 30lb, then the length by which the spring would be stretched is

L = 19 × 30/15

L = 38 inches

understand that i don't know the answers

will someone answer his question

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !