Point Q lies on the line with equation
y + 4 = 2(x - 1). If the x-coordinate of Q is 3, what is
the y-coordinate of Q?

y = 0

Step-by-step explanation:

Substitute x into the equation, then solve for y:

y + 4 = 2(3 - 1)

y + 4 = 2(2)

y + 4 = 4

y = 0

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

lol we need to see what the question is asking about

step-by-step explanation: