How much would 500$ invested at 9% interest compounded annually be worth after 4 years?

$705.79

Step-by-step explanation:

(see attached for reference)

the formula for compound interest is

A = P [1 + (r/n) ]^(nt)

Where:

P = Principal Amount = $500

r = annual interest rate = 9% = 0.09

t = 4 years

n = 1 (compounded annually)

A = 500 [1 + (0.09/1) ]^(1 x 4)

A = 500 [1 + 0.09 ]^(4)

A = 500 [1.09 ]^(4)

A = $705.79

Your answer should be “c” mark me brainliest

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.