An archer shoots an arrow into the air such that
its height at any time, 1, is given by the function
h(t) = - 1612 + kt + 3. If the maximum height of
the arrow occurs at time t = 4, what is the value
of k?

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)