Consider the following equation f(x)=(x^2+4)/(4x^2-4x-8)

Question:

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

The vertical asymptotes are x = 2 or x = -1

Solution:

Given that,

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation

Thus the vertical asymptotes are x = - 1 and x = 2

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

answer: its the third option.

step-by-step explanation:

i just took the test.