Lena draws a square with an area that is greater than the area of rectangle b what are two possible side lengths of lenas square? Explain

Suppose the square Lena draws has the following dimensions:

For the rectangle we have:

Possibility 1. In order for the area of the square to be greater than the area of the rectangle, the following inequality must be true:

Possibility 2. If one side of the rectangle equals the side of the square, that is:

Then, in order for the area of the square to be greater than the area of the rectangle, the following inequality must be true:

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.