The research funds of a certain company were divided among three departments, X, Y, and Z. Which one of the three departments received the greatest proportion of the research funds?1. The research funds received by departments X and Y were in the ratio 3 to 5, respectively.2. The research funds received by departments X and Z were in the ratio 2 to 1, respectively.

Highest received is by department Y

Step-by-step explanation:

Given that the research funds of a certain company were divided among three departments, X, Y, and Z.

The research funds received by departments X and Y were in the ratio 3 to 5, respectively.

The research funds received by departments X and Z were in the ratio 2 to 1, respectively

X:Y = 3:5

X:Z = 2:1

X is common in both the equations so let us take lcd for 3 and 2 = 6

Multiply I equation by 2 and II equation by 3

X:Y = 6:10

X: Z = 6:3

Since X has the same numerical value we can combine these two tog et

X:Y: Z =6:10:3

Highest received is by department Y

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3