Find x, y, z, so that 41, 46, x, y, z has a mean of 50 and a mode of 45

Step-by-step explanation:

as mode is 45 ,two of three is 45

i assume x =y=45

now (41+46+45+45+z)/5=50

177+z=50×5=250

z=250-177=73

so x=45

y=45

z=73

x = 45, y = 45 and z = 73

Step-by-step explanation:

If mode = 45, it means 45 has appeared in the data set more than once

Data set is therefore written as 41, 46, 45, 45 and z; where x = 45 and y = 45

Now that we know x and y, find z.

To find z, if mean of the data set is 50, then it can be written as:

50 = 41 +46 +45 +45 + z/5

Cross multiply to get

50×5 = 177 +z

250 = 177 + z

z = 250 - 177

z= 73

I hope this is clear, please mark as brainliest

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: