{40x+3y=10
{ 20x−7y=5

System of equatio
Please explain

x = , y = 0

Step-by-step explanation:

Given the 2 equations

40x + 3y = 10 → (1)

20x - 7y = 5 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the x- term

- 40x + 14y = - 10 → (3)

Add (1) and (3) term by term, that is

17y = 0 ⇒ y = 0

Substitute y = 0 into either of the 2 equations and solve for x

Substituting y = 0 in (1)

40x + 3(0) = 10, that is

40x = 10 ( divide both sides by 40 )

x = =

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap