If the area, A, of a rectangle is 121, and the length, l, is equal to the width, w, what is the length of the rectangle?

Through trial and error, you should find that 11*11 = 121

A more methodical approach is to let x be the length and width, so x*x = x^2 is the area. Set this equal to 121 and solve for x. Use the square root to undo the square

x^2 = 121

sqrt( x^2 ) = sqrt( 121 )

x = 11

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.