Find the equation of the line passing
through the points (3,-2) and (4, 6).
y = 8x + [?]

y+2=8(x-3)

Step-by-step explanation:

m= (y2-y1)/(x2-x1)

m=(6-(-2))/(4-3)

m=(6+2)/(1)

m=8

8 is your slope. now chose any point that is given to you. fr example you can chose from (3,-2) or (4,6).

i'll chose first one (3,-2) and plug in the equation.

(y-y1)=m(x-x1)

y and x doesn't changes it stay the same. but for y1 and x1 you can plug the point you decided to use. me (3,-2)

y+2=8(x-3)

if you want me to do for the second point you can ask for it..