If f(x) = |x – 4| + 5, find f(1).

10

0

2

8

Step-by-step explanation:

The question is what is f(1) when f(x)= |x – 4| + 5?

Before we start, I want to mention that this function involves the absolute value. The absolute value is when a number is being described as the distance away from the number 0 on a line. When it comes to absolute values, the number is never a negative.

Fore example,  |5| = 5,  |-235| = 235

So let us go straight into the problem!

f(1)=  |(1) – 4| + 5

f(1)=  |(-3)| + 5

f(1)= 3 + 5

f(1)= 8

There you go! When we put in an x-value of 1 into the function we will get 8 as the output or outcome!

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step-by-step explanation: