What is the minimum value of y=2x^2

0

Step-by-step explanation:

What is the minimum value of y= ? To figure this out, we have to remember, when we think of the minimum, we think of the smallest or the least amount or number. So in this case, we can replace x with a number.

What is a small number we can try? How about 2? Let's us replace x with 2.

y=

y= 2()

y=2( 4)

y= 8

Hmmm, I wonder if the value of y can go even smaller or lower. How about we replace "x" with 0?

y=

y=

y= 2(0)

y= 0

That seems like the smallest number that the equation can go? Maybe we should try another number. Let's go to the negative. Let's us try -1?

y=

y=

y=2(1)

y=2

We got y=2 when x=-1!

So it seems like whenever x=0 for this equation we get 0 for the y-value. We can now say that y=0 is the minimum value of this equation!

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: