If there is 4 green marbles and 7 orange marbles in box 1 and 4 green marbles and 5 orange marbles in box 2 what is the probability of picking 2 green marbles?

Out of which box?

I'll answer for Box 1 and Box 2.

So in Box 1, you have 4 + 7 = 11 marbles in total.

Probability of drawing first marble green.

4 (green marbles) / 11 (marbles in total.

Probability of drawing second marble green:

Assuming you already drew a green marble, there's one less green marble, and one less marble in total:

3 / 10.

So the probability of drawing 2 green marbles in Box 1 is:

4 / 11 * 3/10 (since they're independent events) = 12/110 = 6/55

Probability of drawing 2 green marbles in Box 1 is: 6/55.

Now let's move on to Box 2:

You have 4 + 5 = 9 marbles in total.

Probability of drawing first marble green:

4 / 9.

Probability of drawing second marble green:

3/8

Multiply them since they're independent events:

4/9 * 3/8 = 12/72 = 6/36 = 1/6.

Probability of drawing 2 green marbles in Box 2 is 1/6.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3