A car tire is spinning a complete revolution every 0.60 seconds. The valve stem is 2 inches above ground at its lowest point and 26 inches at it's highest. Describe the height of the valve stem as a function of time (seconds) if it begins at the bottom.

Step-by-step explanation:

What is the amplitude, ||, of the height and co-height functions for this car tire

|| = 6

Let () represent the co-height function after rotation by radians, and let () represent the height function after rotation by radians. Write functions for the co-height and for the height in terms of .

() = ()

() = ()  

The co-height graphs are the same but translated 2 inches upward

so our function is:

() = ()  + 2 or

() = ()  + 2

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180