A mass attached to a spring oscillates with a period of 44 sec. After 33 kg are added, the period becomes 55 sec. Assuming that we can neglect any damping or external forces, determine how much mass was originally attached to the spring.

The mass originally attached to the spring was 58.665 kg

Step-by-step explanation:

To solve for this we need to consider the equation for a springs oscillating period:

T =

Here, m = mass of spring

k = spring constant

Since we know that the period increases by 11 (55 - 44) after the extra weight is added, we have the following equations:

   -Equation 1

   -Equation 2

solving both equation simultaneously we get:

m =  58.665 kg

step-by-step explanation:

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i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: