Tim is 4 years older than one-third of Juan's age. In 10 years, Juan will be 6 years older than twice as old as Tim is now. How old is each now?

Tim is 8 years old.

Juan is 12 years old

Step-by-step explanation:

Let x represent the present age of Tim.

Let y represent the present age of Juan.

Tim is 4 years older than one-third of Juan's age. This is expressed as

x = y/3 + 4

In 10 years, Juan will be 6 years older than twice as old as Tim is now. This is expressed as

2(x + 10) = (y + 10) + 6

2x + 20 = y + 16

2x - y = 16 - 20

2x - y = - 4

2y/3 + 8 - y = 4

2y + 24 - 3y = 12

2y - 3y = 12 - 24

- y = - 12

y = 12

Substituting y = 12 into x = y/3 + 4, it becomes

12/3 + 4

x = 4 + 4

x = 8

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)