The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm cubed of water. Find the percent of the cup that is filled with water after 3 seconds.

In 3 seconds the cup is filled with .

Step-by-step explanation:

Given:

2 seconds = water

We need to find the percent of the cup that is filled with water after 3 seconds.

Solution:

Now Given:

The cup was filled at a constant rate.

First we will find the volume of water filled in the cup after 1 seconds.

2 seconds = water

1 seconds = Volume of water filled in 1 second.

By Using Unitary method we get;

Volume of water filled in 1 second =

Now we will find the volume of water filled in the cup after 3 seconds.

1 second = of water is filled

3 seconds = volume of water filled in the cup after 3 seconds

Again by using Unitary method we get;

volume of water filled in the cup after 3 seconds =

Hence In 3 seconds the cup is filled with .

To find the percent of the cup filled with water after 3 seconds we would required the dimensions of the cup which is not available in the question.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

the answer is d

step-by-step explanation: