A trader bought x mangoes at the rate of 4 mangoes for 10 naira five of the mangoes were bad so he sold the remaining at the rate of 5 mangoes for 20 naira and he made a gain of 10 naira how many mangoes did he buy ?

20 mangoes.

Step-by-step explanation:

Given:

Total  number of mangoes, a trader bought =

A trader bought at the rate of 4 mangoes for 10 naira.

Five of the mangoes were bad.

He sold the remaining at the rate of 5 mangoes for 20 naira.

He made a gain of 10 naira

Question asked:

Total  number of mangoes, a trader bought = = ?

Solution:

Unitary method

Cost price of  4 mangoes =  10 naira.

Cost price of  1 mango =

Cost price of mango =

As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold =  

Sale price of 5 mangoes = 20 naira

Sale price of 1 mango =

Sale price of mango =

Now, as we know,

Adding both sides by 20

Multiplying both sides by 2

Dividing both sides by 3

Therefore, total number of mangoes, a trader bought is 20.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

no

step-by-step explanation: