The hensons are fencing a rectangular portion of their lot. They decide to make the length 12 feet longer than the width. They can afford 240 feet of fencing. What should've the dimensions?

The dimensions should be 66 ft by 54 ft

Step-by-step explanation:

Let L represent the length of the rectangular lot.

Let W represent the width of the rectangular lot.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

They can afford 240 feet of fencing. This means that

2(L + W) = 240

Dividing through by 2, it becomes

L + W = 120 - - - - - - - - - - - -1

They decide to make the length 12 feet longer than the width.. This means that

L = W + 12

Substituting L = W + 12 into equation 1, it becomes

W + 12 + W = 120

2W + 12 = 120

2W = 120 - 12

2W = 108

W = 108/2

W = 54 feet

L = W + 12 = 54 + 12

L = 66 feet

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

the answer for your question is

step-by-step explanation: