What is the line with a slope of 3/2 that contains the point (-4,-2)

y = 3/2x + 4

Step-by-step explanation:

First, write your current equation: y= 3/2x + b. Plug in your point to the equation to get this: -2 = 3/2(-4) + b. Multiply 3/2 by -4 to get -6. This is what is should look like: -2 = -6 + b. Add 6 to both sides to get your y-intercept of 4. Go back to your original equation and plug in 4 to b. This is your final equation: y = 3/2x + 4. Hope this helped!