You are choosing between two long-distance fun plans plan a has a monthly fee of $15 with a charge of 0.09 Per minute of long distance calls Plan B has a monthly fee of $12 with a charge of .15 Per minute of long-distance calls how many minutes of long-distance calls in a month make a plan a the better deal

Step-by-step explanation:

This is a system of inequalities problem.  We first need to determine the expression for each phone plan.

Plan A charges $15 whether you use any minutes of long distance or not; if you use long distance you're paying $.09 per minute.  The expression for that plan is

.09x + 15

Plan B charges $12 whether you use any minutes of long distance or not; if you use long distance you're paying $.15 per minute.  The expression for that plan is

.15x + 12

We are asked to determine how many minutes of long distance calls in a month, x, that make plan A the better deal (meaning costs less).  If we want plan A to cost less than plan B, the inequality looks like this:

.09x + 15 < .15x + 12 and "solve" for x:

3 < .06x so

50 < x or x > 50

For plan A to be the better plan, you need to talk at least 50 minutes long distance per month.  Any number of minutes less than 50 makes plan B the cheaper one.

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step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value