Inside the square ABCD, side 15 cm, the point M is considered, so that the triangle ABM is equilateral. Show that:

a) The area of ABCD = 225 cm square,

b) The triangle MDC is isosceles,

c) PLEASE HELP ME!

a) 15*15=225 that is the area

b)see picture that I drew (sorry I have terrible drawing skills on a computer) but in a an isosceles triangle the two legs are congruent and the base is not when you cut a square diagonally as you have done this one the base will not be the same as the other two legs.

Step-by-step explanation:

Step-by-step explanation:

a) area of square: 15 x 15 = 225 cm²

b) The steps are illustrated in the picture.

ΔADM ≅ ΔBCM (sas)

DM = CM

ΔMDC is isoceles

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.