Given f(x)=17-x^2 what is the average rate of change in f(x) over the interval [1, 5]?
0.25

-0.5

4

-6

- 6

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ 1, 5 ], thus

f(b) = f(5) = 17 - 5² = 17 - 25 = - 8

f(a) = f(1) = 17 - 1² = 17 - 1 = 16

average rate of change = = = - 6

answer: ask

step-by-step explanation:

answer: i can’t tell you that

step-by-step explanation: