A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the
spring push when you compress it from 40 cm long down to 15 cm long?

Hooke's Law Formula:

F = k * x

•F = Force

•K = Spring Constant

•X = spring variation

F = ?

K = 70 N/m

X = 40cm - 15cm (ending length - starting length).

But we need to change 'cm' to 'm', so we will divide the result of X by 100.

X= 25/100 → 0.25m

F = 0.25 * 70

F = 17.5 N

- mbsilvaf

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

step-by-step explanation: s