The length of a rectangle is 3 inches longer than it's width. The perimeter of the rectangle is less than 30 inches. Write and solve an inequality to find the width of the rectangle

Step-by-step explanation:

Let W represent the width of the rectangle.

The length of a rectangle is 3 inches longer than it's width. It means that the length of the rectangle is (w + 3) inches

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(length + width)

The perimeter of the rectangle is less than 30 inches. It means that

2(w + w + 3) < 30

2(2w+ 3) < 30

Dividing through by 2, it becomes

2w + 3 < 15

2w < 15 - 3

2w < 12

w < 12/2

w < 6

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what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft