"rectangular storage container with a top made of the same materials as its sides is to have a volume of 10 m3. The length of this base is twice the width. Material for the base costs $10 per square meter. Material for the sides and top costs $6 per square meter. Find the cost of materials for the cheapest such container. (Round your answer to the nearest cent.)"

Cost = $0.08

Step-by-step explanation:

Volume of the Container =

Volume of a Cuboid =lwh

Since the length of the base is twice the width: l=2w

Total Surface Area of a Cuboid = 2(LW+LH+WH)

Material for the base costs $10 per square meter.

Cost of the Base = $10 X LW = $(10LW)

Cost of the Sides and the top =$6(LW+2(LH+WH))=$(6LW+12LH+12WH)

Total Cost=$(10LW)+$(6LW+12LH+12WH)

              =16LW+12LH+12WH

From the volume,

Also, l=2w

Substituting H and L into 16LW+12LH+12WH

The Minimum Value of C(W) is at the point where the derivative=0.

i believe that the answer is

b. y-1=-2(x-4)

hope this !