Quadrilateral WILDWILDW, I, L, D is inscribed in circle OOO. \overline{WI} WI start overline, W, I, end overline is a diameter of circle OOO. What is the measure of \angle D∠Dangle, D? ^\circ ∘ degrees

Question not well presented and diagram is missing

Quadrilateral WILD is inscribed in circle O.

WI is a diameter of circle O.

What is the measure of angle D?

See attached for diagram

Step-by-step explanation:

Summation of opposite angles of a quadrilateral inscribed in a circle is 180°, given that the vertices are on the circle.

Given

<WIL = 45°

<ILD = 109°

In the attached;

<WIL + <WDL = 180° (Opposite angle of quadrilateral)

Substitute 45° for <WIL in the above expression

45° + <WDL = 180° ---- Collect like terms

<WDL = 180° - 45°

<WDL = 135°

Hence, the measure of angle D is 135° (See attached)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet