Let f(x) = x 5 5 − x 4 + x 3 + 2x 2 − 4x + 1. 1. Find f 0 (x) and factor it into linear factors. 2. Find the critical numbers of f(x) on the open interval (0, 3). 3. Find the local extrema of f(x) on the open interval (0, 3). 4. Find the absolute maximum and absolute minimum values of f(x) on the closed interval [0, 3].

F(0)=1

critical values are

df(x)/dx=0

5x^4-4x^3+3X^2+4x-4=0

Solve this equation

The critical values are 2.5 and 0.294

8 2/3 is the answer

step-by-step explanation: just use a calculator

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.