A couple plans to have three children. There are 8 different types of combinations of G girls and
B boys the couple could have, as shown below.
S = {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}
Let A be the event that the first child is a girl and let B be the event that the second child is a girl.
Answer in a decimal:
Find P(A) =

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

m

step-by-step explanation:

c.)

step-by-step explanation: